Wouldn't mild steel be easier to drill than stainless with almost equivalent tensile strength?
Ultimate tensile strength mild steel = 841MPa USS = approx. 0.75*UTS 631MPa
Ultimate tensile strength Stainless = 860MPa USS = approx. 0.75*UTS = 645MPa
Ultimate tensile strength Aluminium = 300-480MPa USS = approx. 0.65*UTS = 195MPa (conservative end)
Motor torque = 20Nm
Where J =
τ = T r / J (1)
where
τ = shear stress (MPa, psi)
T = twisting moment (Nmm, in lb)
r = distance from center to stressed surface in the given position (mm, in)
J = Polar Moment of Inertia of an Area (mm4, in4)
Ultimate tensile strength Stainless
Circular Shaft and Polar Moment of Inertia
Polar Moment of Inertia of a circular solid shaft can be expressed as
J = π R4 / 2
= π (D / 2)4 / 2
= π D4 / 32 (3)
where
D = shaft outside diameter (mm, in)
For our example
Tmax =
T r / J
d
12
mm
T=
20
Nm
d
0.012
m
Tmax
58946275
Pa
Tmax
58.94628
MPa
USS, Aluminum
195
FOS, Aluminium
3.308097
USS, SS
645
FOS, SS
10.94217
Aluminium rod would still have a factor of safety of 3.3x based on the peak torque of the motor.