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Big Dog Brewing
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pH = -log(concentration of Hydrogen Ions)
pH = 8 => C(H+) = 3.35*10^-4 gmol/L
pH = 6 => C(H+) = 0.0025 gmol/L
So we need (0.0025 - 3.35*10^-4)*33 = 0.0707gmol H+ to change pH
Now! I reckon citric acid salt is Calcium Citrate, formula Ca3(C5H4O5COOH)2, molecular weight = 498.46g/gmol.
2 mol of H+ released per 1 mol of Calcium Citrate in solution => need 0.0354 gmol of Calcium Citrate
=> 17.6g of Calcium Citrate ("Citric Acid" salt)... theoretically...
Damn I shouldnt have had that coffee.
Yes but your H+ ions are being removed by the alkalinity in the water and any buffering capacity that is present. The amount of citric acid to achieve the same pH change in different waters will be very different, and controlled by what is in the water to start with. What you will notice if you add it gradually is the pH doesnt change much, then suddenly you overcome the buffering capacity and a small amount of acid makes a big difference in pH. I would also be surprised if citric acid from the supermarket is completely anhydrous which might make a difference to your molecular weight. Hopefully your number will be a ballpark starting point anyway.