Did i mention im still new and i don't know half the words of phrases you said! haha
I got the jist of it but.
Things to clarify:
liquor: Define.
Mashtun: Define
You say FV 23L = Mash in was 14L + 9L water?. to make up 23L?
I understand losses and which one is which, but this confuses me; "so 9L + 7L + 6L = 22L sparge liquor." 9L of water to add? + 7L lost in boil and trub + 6L (mashtun?) = 22L sparge liquor (this figure confuses me, what is it?)
Also, explain "Total liquor used in mash and sparge 22+14 = 36L."
Definition of Liquor "An alcoholic beverage made by distillation rather than by fermentation."
Thanks mate.
Thought Forstar's post was excellent, obviously you are very new to the terms etc. Tun = Tank/Vessel/Container, Mash Tun = Vessel used for mashing the grist. Grist = Ground up grains etc. Brewing Liquor = Water plus any salts or water treatment (in most hombrewing situations, Liquor = Water). HLT = Hot Liquor Tun (tank used for preparing/heating your brewing liquor). FV = Fermentation Vessel
FV = 23L (you want 23L in your Fermenter)
Mash in 14L (Fourstar explained that he was using 5kg of grain with a liquor to grist ratio of 2.8L per kg of grain, this = 14L of liquor/water)
23L is our final volume, minus the mash in we are left with the following to make it up = 9L
Final volume = in the fermenter, So you want 23L in the fermenter and have added 14L to the mash tun. So you need another 9L of liquor!
1L to 1kg of spent grain is your grain loss post mash
There will be retention of moisture by the grain. Means that of the 14L that 1L will be retained per 1 kg of grain after draining (5Kg will retain 5L). So 14L - 5L = 9L
add 1L~ for mashtun deadspace losses
There will be space in the bottom of the tun, not all of the wort can be drained off, this amount will depend upon mashtun geometry and manifold design.
This explains that after draining the mashtun, of the original 14L you will only have 8L of wort due to losses (14 - 5 - 1)
assume a boil off of around 5L (15-16%~) per hour and around 2L of losses (trub etc) (so lets say 7)
During boiling losses will occur due to evaporation, Fourstar's example is 7L
Fourstar explained that after adding 14L to the mash you still need 9L to provide the target of 23L, however the losses above need to be added to this figure. To replace the amounts lost during the process and maintain the required finished volume.
You say:
this confuses me; "so 9L + 7L + 6L = 22L sparge liquor.
Hope you can now see that the 9L was what was required to reach the 23L target. Losses need to be added to this 9L. Add the boiloff volume of 7L and the Mashtun loss of 6L (5l grain retention and 1L deadspace).
So there 9L + 7L + 6L = 22L of Sparge liquor.
Peice a piss, this brewing game eh!
Screwy