^ with your pool chilling method;
How long in the cube before it goes into the pool?
How long does it take for the temp to drop to pool water temp?
Do you think it would be the same affect with water in a 44Gal drum?
how did you measure 1.026? Refractometer or hydrometer
it seems to be a big thing now, especially with the NEIPAs.... but just all late/dry hops and 15min "bittering" additionGordon Strong has done a few Beer Smith podcast's he does a beer with just flame out additions.
Nothing. The hops are already removed in no chilling because they get left behind in the kettle.what if you remove the hops before the chilling / no-chilling part? :/
Nothing. The hops are already removed in no chilling because they get left behind in the kettle.
In any case though, it's isomerisation of the alpha acids, they'll be in the wort regardless of the hops being removed or not.
except for cube hops!Nothing. The hops are already removed in no chilling because they get left behind in the kettle.
In any case though, it's isomerisation of the alpha acids, they'll be in the wort regardless of the hops being removed or not.
If you mashed at 75 and have plastic tastes, you have a world of things to work out before worrying about shifting hop additions.
For new cubes, you can fill with boiling water, let cool, then taste the water. If it tastes like plastic, repeat the process until it doesn't.
Make sure all hoses are food grade silicon, not pvc or similar.
For mash temp, invest in a good thermometer and a couple of spares. Check all in boiling, near freezing and somewhere in mash temp range and see if there's any discrepancy.
In any case though, it's isomerisation of the alpha acids, they'll be in the wort regardless of the hops being removed or not.
mmmm I thought it had to do with other chemicals, I'm not sure if I understand why this is happening then... so the problem is from boiling to 90º??
Rocker1986 said that it doesn't matter if you remove or not the hops from the kettle/fermenter after boiling because the alpha acids are already dissolved and they keep the isomerization process, you confirm the formula is not linear or stops at one temperature but it is continuous and logarithmic so that means with time and temp they will continue to "create bitterness" but probably at an insignificant rate when they are down a particular threshold.. the point is to find which is the temperature to chill the wort without getting too crazy with the chilling procedure, when is it "safe" to stop "fast chilling" and leave it into the fridge or cooling "slowly"? What is this "sweetspot"? 60, 50, 40, 30? Or maybe the question is not to find a perfect value but the one that makes you happy, so maybe it would be more interesting to make a poll...Research suggests that is not the mechanism involved as raw alpha acids (before isomerisation) are even less soluble than iso alpha acids. Since the alpha acids are largely contained in the lupulin glands which are dominated by their wax / oil content, it follows that the majority of isomerisation will occur before extraction.
Another complication is that raw alpha acids are 10,000 to 100,000 times more soluble in HDPE than in wort* and have been shown to be strongly surface active, so a large (but very hard to predict) proportion of the alpha extracted from the hops will not end up in the wort at all.
No.
The rate of isomerisation reduces with temperature but it never reaches zero**. Once you are below about 70 degreees it is slow enough that you have to do something unusual for it to affect the isomerisation rate: like, for instance, filling your wort into a large plastic container at high temperature without cooling.
Footnotes:
* The rate of migration into the HDPE is very slow, so it is likely that the surface effect dominates in short time scales. I am unaware of any research that quantifies this, it is unlikely have been done since the part of the industry that funds research doesn't use plastic containers for wort.
** We've been through this many times before. The rate drops by a bit more than half for each 10 oC reduction in temperature. If you like maths, SQRT 6 is a good approximation of the reduction rate. Another way of thinking of this is that the rate reduces by a factor of 10 when the temperature drops by ~26 degrees ( ln10 / ln 6 = 1.28).
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