Archie
Not a stupid question at all, and reasonably easy to answer. Basically, you work out the kilo's of grain, multiplied by their extract number, and divide by the litres in yer kettle. I do everything by hand, so work it out the american way, cause all the books I have are seppo ones. Check out www.howtobrew.com for more detailed instructions.
EG 5kg pale malt x 2.2 (to get to pounds) x 36 (extract potential) / 6.5 gallons (25L)
= 11 x 36 = 396 / 6.5
= 60.92, or 61
so, your 100% efficiency would be about 1.061. Say you got 1.048, divide 48 by 61, and it will give ya your efficiency
48/61 = 0.786, times 100 (if ya can be bothered) gives you about 78.6% efficiency.
I am sure it is easy enough to do it in kilo's and litres, but I am just used to pounds/gallons. How to brew will give you all the extract potentials of most malts, and also tell ya how to convert those numbers for pounds, into numbers for kilos. From memory, it is multiply by 8.34?
Easier way to work it all out is to punch all yer figures into promash or similar, and let that tell ya how ya did!
Hope that helps a little
Trent