Figures below reflect my mash efficiency. My overall efficiency depends quite a bit on how much hops I add to the recipe, more hops means I leave more in the kettle.
This particular data set has no (linear) correlation between pre boil volume and efficiency
As has been pointed out, your fixed losses are more significant with smaller batches. Mashtun dead volume, kettle dead volume, chiller dead volume. Also you typically have dead volume in your fermenter.
If you measure the SG of your last runnings, you can calculate how much sugar is left in the mashtun. You need to know your water volume (dead volume + loss to grain) and make an assumption regarding conversion efficiency.
Also when batch sparging, the ratio of mash runoff to sparge runnoff affects efficiency, I have not crunched the numbers but others that have state that the optimal efficiency is achieved (all else being equal) when both runoff volumes are equal.
Code:
grain.mass efficiency pre_boil.vol
belgian01b 6.30 0.83 33
marzen NA NA NA
OzPaleAle 3.80 0.89 34
OzWheat 4.50 0.87 34
OzWheat_2 5.00 0.85 33
steam NA NA NA
Stout02 5.54 0.74 33
sweetStout 4.85 0.83 35
WA_APA NA NA NA
WA_APA_4_HopHead 5.33 0.91 34
WA_APA_5-02 5.33 0.85 34
WA_APA_5 5.33 0.84 35
WA_APA_6-01 4.53 0.86 34
WA_APA_7-01 5.13 0.84 35
WA_APA_more_malt 2 5.33 0.88 34
WA_APA_more_malt 3 5.42 NA 34
WA_APA_more_malt NA NA NA
Wheat_3 3.80 0.87 35
This particular data set has no (linear) correlation between pre boil volume and efficiency
As has been pointed out, your fixed losses are more significant with smaller batches. Mashtun dead volume, kettle dead volume, chiller dead volume. Also you typically have dead volume in your fermenter.
If you measure the SG of your last runnings, you can calculate how much sugar is left in the mashtun. You need to know your water volume (dead volume + loss to grain) and make an assumption regarding conversion efficiency.
Also when batch sparging, the ratio of mash runoff to sparge runnoff affects efficiency, I have not crunched the numbers but others that have state that the optimal efficiency is achieved (all else being equal) when both runoff volumes are equal.