Ckilner
Well-Known Member
I've done some reading and researching on this and have also picked up some good information from other threads. Can anyone confirm my calculations?
I have water which is as follows:
Ca = 155 mg/l
CaCO3 = 389 mg/l so multiplying by 1.22 gives HCO3 = 475 mg/l
If I boil and splash the water then CO2 is released and the CaCO3 drops out so this reduces the bicarbonate concentration and also reduces the calcium.
I understand that the best I can expect is that the bicarbonate reduces to 80 mg/l which gives a CaCO3 value of 65 mg/l
The calcium is also reduced so using the formula:
Calciumend(ppm)=Calciumstart(ppm)-((HCO3start(ppm) - HCO3end(ppm))/3.05)
so in my example:
Calciumend(ppm) = 155-((475-80)/3.05) gives a new calcium value of 25 mg/l
Am I anywhere near the mark?
I have water which is as follows:
Ca = 155 mg/l
CaCO3 = 389 mg/l so multiplying by 1.22 gives HCO3 = 475 mg/l
If I boil and splash the water then CO2 is released and the CaCO3 drops out so this reduces the bicarbonate concentration and also reduces the calcium.
I understand that the best I can expect is that the bicarbonate reduces to 80 mg/l which gives a CaCO3 value of 65 mg/l
The calcium is also reduced so using the formula:
Calciumend(ppm)=Calciumstart(ppm)-((HCO3start(ppm) - HCO3end(ppm))/3.05)
so in my example:
Calciumend(ppm) = 155-((475-80)/3.05) gives a new calcium value of 25 mg/l
Am I anywhere near the mark?