The wife likes hoppy IPAs so helped her with a brew for a competition. Totally forgot to allow for the wort trapped by 255 grams of hops. With a normal brew the wort trapped by the hops is accounted for by my program as what is left in the kettle. This time my error made for less wort in the fermentor. No loss for me as I will never drink the stuff. I would like to find a way to account for it in the future.
So has anyone ever worked out just how much wort gets trapped by hops? I could work it out over time but if someone has already figured it out then that would be great.
So has anyone ever worked out just how much wort gets trapped by hops? I could work it out over time but if someone has already figured it out then that would be great.